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Friday, May 18, 2012

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HCL Comnet Placement Paper-1 2012

  • Friday, May 18, 2012
  • Krishna Mohan Roy
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  • Welcome to HCL Comnet Placement Paper 2012.
    HCL Comnet Placement Paper 2012
    Here you will find HCL Comnet Placement Paper Pattern and Download questions of HCL Comnet Placement Paper January 2012 with Answers & Solutions.

    Company            :-      HCL.
    Category            :-      Placement Papers.
    Location             :-      Gurgaon - Delhi / NCR


    HCL Comnet Placement Paper January 2012:-

    1. We should not read after a write to a file without an intervening call to fflush(), fseek() or rewind() < TRUE/FALSE>

    Ans. True

    2. 1/3 of girls , 1/2 of boys go to canteen .What factor and total number of classmates go to canteen.

    Ans: Cannot be determined.

    3. The price of a product is reduced by 30% . By what percentage should it be increased to make it 100%

    Ans: 42.857%

    4. A worker is paid Rs.20/- for a full days work. He works 1,1/3,2/3,1/8.3/4 days in a week. What is the total amount paid for that worker ?

    Ans : 57.50

    5. Each side of a rectangle is increased by 100% .By what percentage does the area increase?

    Ans : 300%

    6.main( )
        {
          int x = 5;
          printf(“%d %d”, x++, ++x);
          return 0;
            }

    a) Error    
    b) 6, 6   
    c) 5, 7   
    d) 7, 6


    7. main( )
          {
               int z = 4;
               printf( “%d”, printf(“ %d %d “, z, z));
          }

    a)  4 4 3        
    b)  4 4 5     
    c)  4 4 4       
    d)  Error


    8. int i = 0;
         main( )
         {
              printf(“i = %d”, i);
              i++;
              val( );
              printf(“After i=%d”, i);
              val( );
         }
         val( )
         {
             i =100;
             printf(“val’s  i=%d\n”, i);
             i++;
         }

    a) i =0             
    b) i=0                          
    c) Error                      
    d) None of the above
       

    9.  main( )
          {
               int a[ ] = { 10, 20, 30, 40, 50};
               int j;
               for (j = 0;  j < 5; j++)
               {
                   printf(“ \n %d”, * a);
                   a ++;
                }
           }

    a) 0..5   
    b) 0..4            
    c) Error         
    d) None of the above


    10. main( )
          {
              int a[5] = {2, 4, 6, 8, 10);
              int i, b =5;
              for(i=0; i<5; i++)
              {
                    f(a[i], &b);
                    printf(“\n %d %d”, a[i], b);
               }
             }
             f(int x, int *y)
             {
                    x = *(y) +=2;
              }


    a) 2    7                       
    b)    4   9                                 
    c) 7     2          
    d) Error

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